You have to assemble the barrows yourself from component parts that are collected together for you by a shop assistant. If, instead of choosing one left handle and one right handle, the assistant chooses a pair at random, what is the probability that you end up with a barrow with a correct left and right pair of handles?
Supplementary question: What is the probability that the buyer will notice that he has two left handles 1) before leaving the shop? 2) before commencing assembly? 3) during assembly? 4) only after he has finished?
4 comments:
I dub thee Mark Barrowman. Obviously you are John's identical twin brother.
Oooo, I know, I know! :)
About 56% chance you will get a pair of correct handles. And the probability of you noticing prior to completion that you haven't? About 0.001%. And that's scientific.
Aw, dammit, I knew I shoulda studied...
Pearl
Probability does not exist in real life - you either do or you don't, it is or isn't - as my art teacher used to say. Still annoying when it happens though.
Post a Comment